Apographum schediasmatis a Newtono olim scripti Isaac Newton c. 465 words The Newton Project Oxford 2020 Newton Project, University of Oxford

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 13 November 1665, in English with some Latin, c. 465 words, 2 pp of 2 fos. 2 pp of 2 fos.

in English with some Latin

 MS Add. 3968, ff. 1r-2v, Cambridge University Library, Cambridge, UK UKCambridgeCambridge University Library Portsmouth Collection MS Add. 3968, ff. 1r-2v 13 November 1665 England English Latin Isaac Newton ScienceMathematics Transcription by Marie Soulier Transcription by Michelle Pfeffer Transcription continued by Robert Ralley Transcription completed by Robert Ralley. Code audited by Michael Hawkins.
Apographum Schediasmatis a Newtono olim scripti cui forte appositum fuit scribendi tempus 13 Novem. 1665.
Probleme

An equation being given expressing the Relation of two or more lines x, y & z described in the same time by two or more moving bodies A, B, C, & to find the relation of their velocities p, q, r, &c

Solution

Set all yethe terms on one side of the Equation that they become equal to nothing. Multiply each term by so many times px as x hath dimensions in that term. Secondly multiply each term by so many times qy as y hath dimensions in it. Thirdly multiply each term by so many times rz as z hath dimensions in it &c. The summ of all these products shall be equal to nothing. Which Equation gives the relation of p, q, r, &c.

Or more generally thus. Order the Equation according to the dimensions of x, & putting a & b for any two numbers whether rational or not, multiply the thers thereof by any part of this Progression a⁢p−3⁢b⁢px.a⁢p−2⁢b⁢px.a⁢p−b⁢px.a⁢px.a⁢p+b⁢px.a⁢p+2⁢b⁢px.a⁢p +3⁢b⁢px.&c. Also order the Equation according to the dimensions of y & multiply the terms of it by this Progression a⁢q−3⁢b⁢qy.a⁢q−2⁢b⁢qy.a⁢q−b⁢qy.a⁢qy.a⁢q+b⁢qy.a⁢q+2⁢b⁢qy.a⁢q+3⁢b⁢qy.&c Also order it according to the dimensions of z & multiply its terms by this Progression a⁢r−3⁢b⁢rz.a⁢r−2⁢b⁢rz.a⁢r−b⁢rz.a⁢rz.a⁢r+b⁢rz.a⁢r+2⁢b⁢rz.a⁢r+3⁢b⁢rz. &c. The summ of these products shall bee equal to nothing. Which equation gives the relation of p, q, r, &c. Examples. Example 1. If the propounded Equation be x3−2⁢x⁢x⁢y+4⁢x⁢x−7⁢x⁢y⁢y−y3−103=0. By the precedent Rule the first operation will produce 3⁢x⁢x⁢p−4⁢x⁢y⁢p+8⁢x⁢p+7⁢y⁢y⁢p. The second produceth −2⁢x⁢x⁢q+14⁢x⁢y⁢q−3⁢y⁢y⁢q. And these two added together make 3⁢x⁢x⁢p−4⁢x⁢y⁢p+8⁢x⁢p+7⁢y⁢y⁢p−2⁢x⁢x⁢q+14⁢x⁢y⁢q−3⁢y⁢y⁢q=0. Example 2. If the Equation be x3−2⁢a⁢a⁢y+z⁢z⁢x−y⁢y⁢x+z⁢y⁢y−z3=0 the first operation will produce 3⁢p⁢x⁢x+p⁢z⁢z−p⁢y⁢y, the second −2⁢a⁢a⁢q−2⁢y⁢x⁢q+2⁢z⁢y⁢q, the third +2⁢z⁢x⁢r−y⁢y⁢r−3⁢z⁢z⁢r. The summ of wchwhich is 3⁢p⁢x⁢x+p⁢z⁢z−p⁢y⁢y−2⁢a⁢a⁢q−2⁢y⁢x⁢q+2⁢z⁢y⁢q+2⁢z⁢x⁢r−y⁢y⁢r−3⁢z⁢z⁢r=0. Demonstration If two bodies A & B move uniformly, the one successively succesively from a to c, e, g &c the other in the same times from b to d, f, h &c then are the lines ac & bd, ce & df, eg & fh &c in the same proportion to one another as are the velocities p & q wherewith the bodies describe them And2 And tho they move not uniformly yet are the infinitely little lines wchwhich each moment they describe, as the velocities are which they have while they describe them. As if the body A with the velocity p describe the infinitely little line po in one moment, the body B with the velocity q will describe the line qo in the same moment For p.q:::po. qo. So that if the described lines be x & y in one moment they will be x+po & y+qo in the next moment. Now if the equation expressing the relation between the lines x & y be for instance r⁢x+x⁢x−y⁢y=0